OBJECTIVE:
APPARATUS:
INTRODUCTION:
For an npn transistor the collector is positive
relative to the emitter.
The base-emitter circuit acts like a diode and is normally conducting
(i.e. forward-biased). The base-collector circuit also acts as a diode but is
normally non-conducting (reverse biased) if no current flows in the
base-emitter circuit. However when current
flows in the base-emitter circuit, the high concentration gradient of
carriers in the very thin base gives an appreciable diffusion current to the
reversed biased collector.
The resulting
collector current depends on the base current
. We write
I
where
is the current amplification factor.
SUGGESTED EXPERIMENTS:
1. CURRENT Amplification: Measure ![]() ![]() |
Figure 2
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Repeat the readings for ten reasonably spaced (higher)
settings of the voltage divider (i.e. higher and hence higher
.
Calculate
) and plot it against
. Over what range of
I
is
reasonably constant?
Repeat the above but with emitter to collector voltage
now at 7 V.
Graph V vs V
and calculate the voltage gain G at the steeply changing
part of your graph. The value of V
at the center of this region we
call the ``operating voltage'' of the amplifier.
How would the gain change if the load resistance was
instead of
?
Adjust the voltage divider until the is close to the ``operating
voltage'' found in #3.
Vary (and record) the amplitude of the input signal
from small values to those which overdrive the amplifier
and produce considerable distortion in the output Y.
Observe and record the effect of changing V
to values outside of the
operating range (where
is constant).